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Question
unit 5: mass-mole-atoms of elements
using avogadros number, determine the number of atoms in each of the following. also write the elements symbol. (ex: carbon = c)
- 0.250 mol silver to atoms of silver
- $8.56 \times 10^{-3}$ mol sodium to atoms of sodium
- 35.4 mol bismuth to atoms of bismuth
determine the number of moles in each of the following. also write the name of the element.
- $3.25 \times 10^{20}$ atoms pb to mol pb
- $4.96 \times 10^{24}$ atoms au to mol au
- $1.56 \times 10^{23}$ atoms sn to mol sn
use the molar mass of the element to convert from mol to g.
- 0.375 mol calcium to g calcium
- $8.56 \times 10^{-3}$ mol potassium to g potassium
- 55 mol silicon to g silicon
Step1: Moles to atoms (Ag)
Use Avogadro's number $N_A = 6.022 \times 10^{23}\ \text{atoms/mol}$
$\text{Atoms of Ag} = 0.250\ \text{mol} \times 6.022 \times 10^{23}\ \text{atoms/mol}$
Step2: Moles to atoms (Na)
$\text{Atoms of Na} = 8.56 \times 10^{-3}\ \text{mol} \times 6.022 \times 10^{23}\ \text{atoms/mol}$
Step3: Moles to atoms (Bi)
$\text{Atoms of Bi} = 35.4\ \text{mol} \times 6.022 \times 10^{23}\ \text{atoms/mol}$
Step4: Atoms to moles (Pb)
Element: Lead (Pb)
$\text{Moles of Pb} = \frac{3.25 \times 10^{20}\ \text{atoms}}{6.022 \times 10^{23}\ \text{atoms/mol}}$
Step5: Atoms to moles (Au)
Element: Gold (Au)
$\text{Moles of Au} = \frac{4.96 \times 10^{24}\ \text{atoms}}{6.022 \times 10^{23}\ \text{atoms/mol}}$
Step6: Atoms to moles (Sn)
Element: Tin (Sn)
$\text{Moles of Sn} = \frac{1.56 \times 10^{23}\ \text{atoms}}{6.022 \times 10^{23}\ \text{atoms/mol}}$
Step7: Moles to mass (Ca)
Molar mass of Ca = $40.08\ \text{g/mol}$
$\text{Mass of Ca} = 0.375\ \text{mol} \times 40.08\ \text{g/mol}$
Step8: Moles to mass (K)
Molar mass of K = $39.10\ \text{g/mol}$
$\text{Mass of K} = 8.56 \times 10^{-3}\ \text{mol} \times 39.10\ \text{g/mol}$
Step9: Moles to mass (Si)
Molar mass of Si = $28.09\ \text{g/mol}$
$\text{Mass of Si} = 55\ \text{mol} \times 28.09\ \text{g/mol}$
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- $1.51 \times 10^{23}$ atoms of Ag
- $5.15 \times 10^{21}$ atoms of Na
- $2.13 \times 10^{25}$ atoms of Bi
- $5.40 \times 10^{-4}$ mol of Lead (Pb)
- $8.24$ mol of Gold (Au)
- $0.259$ mol of Tin (Sn)
- $15.0$ g of Ca
- $0.335$ g of K
- $1545$ g (or $1.5 \times 10^3$ g) of Si