Question

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table.
drive - thru restaurant

	a	b	c	d
order not accurate	37	53	34	10

if one order is selected, find the probability of getting food that is not from restaurant a.
the probability of getting food that is not from restaurant a is
(round to three decimal places as needed.)

Explanation:

Step1: Calculate total orders

First, we find the total number of orders by summing up all the values in the table.
For Restaurant A: \(321 + 37 = 358\)
For Restaurant B: \(271 + 53 = 324\)
For Restaurant C: \(246 + 34 = 280\)
For Restaurant D: \(135 + 10 = 145\)
Total orders \(= 358 + 324 + 280 + 145 = 1107\)

Step2: Calculate orders not from A

Orders not from Restaurant A are the sum of orders from B, C, D.
\(324 + 280 + 145 = 749\)

Step3: Calculate probability

Probability \(= \frac{\text{Orders not from A}}{\text{Total orders}} = \frac{749}{1107} \approx 0.677\)

Answer:

\(0.677\)