Question

use the data in the following table, which lists drive - thru order accuracy at popular fast - food chains. assume that orders are randomly selected from those included in the table.
drive - thru restaurant

	a	b	c	d
order not accurate	30	54	38	20

if one order is selected, find the probability of getting an order from restaurant a or an order that is accurate. are the events of selecting an order from restaurant a and selecting an accurate order disjoint events?
the probability of getting an order from restaurant a or an order that is accurate is 0.869. (round to three decimal places as needed.)
are the events of selecting an order from restaurant a and selecting an accurate order disjoint events?
the events blank disjoint because it blank possible to blank

Explanation:

Step1: Calculate total number of orders

$314 + 273+742 + 138+39+54+29+20=1609$

Step2: Calculate number of orders from Restaurant A

$314 + 39=353$

Step3: Calculate number of accurate orders

$314+273 + 742+138 = 1467$

Step4: Calculate number of accurate orders from Restaurant A

$314$

Step5: Use the addition - rule for probability

$P(A\ or\ accurate)=P(A)+P(accurate)-P(A\ and\ accurate)$
$P(A)=\frac{353}{1609}$, $P(accurate)=\frac{1467}{1609}$, $P(A\ and\ accurate)=\frac{314}{1609}$
$P(A\ or\ accurate)=\frac{353 + 1467-314}{1609}=\frac{1506}{1609}\approx0.936$

Step6: Determine if events are disjoint

The events are not disjoint because it is possible to get an accurate order from Restaurant A.

Answer:

The probability of getting an order from Restaurant A or an order that is accurate is approximately $0.936$. The events are not disjoint because it is possible to get an accurate order from Restaurant A.