Question

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table.
drive - thru restaurant

	a	b	c	d
order not accurate	35	55	33	16

if one order is selected, find the probability of getting an order from restaurant a or an order that is accurate. are the events of selecting an order from restaurant a and selecting an accurate order disjoint events?
the probability of getting an order from restaurant a or an order that is accurate is
(round to three decimal places as needed.)
are the events of selecting an order from restaurant a and selecting an accurate order disjoint events?
the events disjoint because it possible to

Explanation:

Step1: Calculate total number of orders

$323 + 267+248 + 142+35 + 55+33 + 16=1119$

Step2: Calculate number of orders from Restaurant A

$323 + 35=358$

Step3: Calculate number of accurate orders

$323+267 + 248+142 = 980$

Step4: Calculate number of accurate orders from Restaurant A

$323$

Step5: Use the addition - rule for probability

$P(A\ or\ accurate)=P(A)+P(accurate)-P(A\ and\ accurate)$
$P(A)=\frac{358}{1119}$, $P(accurate)=\frac{980}{1119}$, $P(A\ and\ accurate)=\frac{323}{1119}$
$P(A\ or\ accurate)=\frac{358 + 980-323}{1119}=\frac{1015}{1119}\approx0.907$

Step6: Determine if events are disjoint

Disjoint events cannot occur at the same time. Since there are accurate orders from Restaurant A (323 of them), it is possible to select an order from Restaurant A and have it be accurate. So the events are not disjoint.

Answer:

The probability of getting an order from Restaurant A or an order that is accurate is $0.907$.
The events are not disjoint because it is possible to get an accurate order from Restaurant A.