Question

use the references to access important values if needed for this question. 1. how many grams of sodium nitrate are present in 3.66 moles of this compound? grams. 2. how many moles of sodium nitrate are present in 2.93 grams of this compound? moles. submit answer retry entire group 5 more group attempts remaining

Explanation:

Step1: Calculate molar - mass of sodium nitrate ($NaNO_3$)

The molar mass of $Na$ is approximately $22.99\ g/mol$, $N$ is approximately $14.01\ g/mol$, and $O$ is approximately $16.00\ g/mol$. For $NaNO_3$, $M = 22.99+14.01 + 3\times16.00=84.99\ g/mol$.

Step2: Find mass given moles for the first question

We use the formula $m = n\times M$, where $n = 3.66\ mol$ and $M = 84.99\ g/mol$. So $m=3.66\times84.99 = 310.0634\ g\approx310.1\ g$.

Step3: Find moles given mass for the second question

We use the formula $n=\frac{m}{M}$, where $m = 2.93\ g$ and $M = 84.99\ g/mol$. So $n=\frac{2.93}{84.99}\approx0.0345\ mol$.

Answer:

1. $310.1$ grams
2. $0.0345$ moles