Question

use table s & i to help you 5. a 10.0 cm³ sample of aluminum will have a mass of: 6. a 10.0 gram sample of aluminum will have a volume of:

Explanation:

To solve these problems, we need the density of aluminum. The density of aluminum is a known value: $
ho = 2.70\ \text{g/cm}^3$ (this value is typically found in tables, as hinted by "Use Table S & T").

Problem 5: Mass of a 10.0 cm³ aluminum sample

Step 1: Recall the density formula

Density is defined as mass per unit volume: $
ho = \frac{m}{V}$, where $
ho$ = density, $m$ = mass, and $V$ = volume.

Step 2: Rearrange the formula to solve for mass

We need to find $m$, so rearrange the formula: $m =
ho \times V$.

Step 3: Substitute the known values

Given $
ho = 2.70\ \text{g/cm}^3$ and $V = 10.0\ \text{cm}^3$, substitute into the formula:
$m = 2.70\ \text{g/cm}^3 \times 10.0\ \text{cm}^3$

Step 4: Calculate the mass

Multiply the values: $m = 27.0\ \text{g}$

Problem 6: Volume of a 10.0 gram aluminum sample

Step 1: Recall the density formula

Again, use $
ho = \frac{m}{V}$.

Step 2: Rearrange the formula to solve for volume

We need to find $V$, so rearrange: $V = \frac{m}{
ho}$.

Step 3: Substitute the known values

Given $m = 10.0\ \text{g}$ and $
ho = 2.70\ \text{g/cm}^3$, substitute:
$V = \frac{10.0\ \text{g}}{2.70\ \text{g/cm}^3}$

Step 4: Calculate the volume

Divide the values: $V \approx 3.70\ \text{cm}^3$ (rounded to three significant figures)

Answer:

s:

1. The mass of the 10.0 cm³ aluminum sample is $\boldsymbol{27.0\ \text{g}}$.
2. The volume of the 10.0 gram aluminum sample is approximately $\boldsymbol{3.70\ \text{cm}^3}$.