Question

1. use the triangle to the left to determine the following: what is the mass of a golf ball that has a density of 2.5 g/cm³ and when placed in a graduated cylinder makes the water rise from 12 ml to 20 ml? show work: answer: ______________

Explanation:

Step1: Determine the volume of the golf - ball

The volume of the golf - ball is equal to the volume of water it displaces. The initial volume of water is $V_1 = 12\ mL$ and the final volume is $V_2=20\ mL$. So the volume of the golf - ball $V = V_2 - V_1$.
$V=(20 - 12)\ mL=8\ mL$. Since $1\ mL = 1\ cm^3$, then $V = 8\ cm^3$.

Step2: Use the density formula to find the mass

The density formula is $D=\frac{M}{V}$, where $D$ is density, $M$ is mass, and $V$ is volume. We want to find $M$, and we know that $D = 2.5\ g/cm^3$ and $V = 8\ cm^3$. Rearranging the formula for $M$ gives $M=D\times V$.
$M = 2.5\ g/cm^3\times8\ cm^3=20\ g$.

Answer:

$20\ g$