Question

velocity review guide

1. what is the difference between distance and displacement?
2. what is the difference between speed and velocity?
3. what do we mean when we say constant speed or constant acceleration?
4. what is the definition of acceleration?
5. how do we find the average speed of an object?

a. rearrange the equation to solve for time.
b. rearrange the equation to solve for distance.

1. how do we find the acceleration of an object?

a. rearrange the equation to solve for speed.
b. rearrange the equation to solve for time.

Explanation:

1. Distance is a scalar, total path length; displacement is a vector, straight - line from start to end.
2. Speed is scalar, rate of distance covered; velocity is vector, rate of displacement change.
3. Constant speed: unchanging rate of distance covered; constant acceleration: unchanging rate of velocity change.
4. Acceleration is the rate of change of velocity, $a=\frac{\Delta v}{\Delta t}$.
5. Average speed $v_{avg}=\frac{d}{t}$. To solve for time $t = \frac{d}{v_{avg}}$, for distance $d=v_{avg}\times t$.
6. Acceleration $a=\frac{v - u}{t}$. To solve for speed $v = u+at$, for time $t=\frac{v - u}{a}$.

Answer:

1. Distance is a scalar quantity representing the total path length traveled, while displacement is a vector quantity representing the straight - line distance and direction from the initial to the final position.
2. Speed is a scalar quantity that measures the rate of distance traveled per unit time, while velocity is a vector quantity that measures the rate of displacement per unit time.
3. Constant speed means the object covers equal distances in equal intervals of time. Constant acceleration means the object's velocity changes by an equal amount in equal intervals of time.
4. Acceleration is the rate of change of velocity with respect to time, given by the formula $a=\frac{\Delta v}{\Delta t}$, where $\Delta v$ is the change in velocity and $\Delta t$ is the change in time.
5. The average speed of an object is found by dividing the total distance traveled by the total time taken, $v_{avg}=\frac{d}{t}$.

• a. To solve for time, $t=\frac{d}{v_{avg}}$.
• b. To solve for distance, $d = v_{avg}\times t$.

1. The acceleration of an object is found by dividing the change in velocity by the time taken, $a=\frac{v - u}{t}$, where $v$ is the final velocity, $u$ is the initial velocity, and $t$ is the time.

• a. To solve for speed, $v=u + at$.
• b. To solve for time, $t=\frac{v - u}{a}$.