Question

if voltage in a circuit is constant, the current can be cut to half of its original value by changing the resistance to ______ its original value. which best completes the statement? one - fourth one - half two times four times

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $V = IR$, where $V$ is voltage, $I$ is current and $R$ is resistance.

Step2: Let the original current be $I_1$ and resistance be $R_1$, and new - current be $I_2$ and resistance be $R_2$. Since $V$ is constant, $V = I_1R_1=I_2R_2$.

We know that $I_2=\frac{1}{2}I_1$.

Step3: Substitute $I_2$ into the equation

Substitute $I_2=\frac{1}{2}I_1$ into $I_1R_1 = I_2R_2$. We get $I_1R_1=\frac{1}{2}I_1R_2$.

Step4: Solve for $R_2$

Cancel out $I_1$ from both sides of the equation $I_1R_1=\frac{1}{2}I_1R_2$. We have $R_2 = 2R_1$.

Answer:

C. two times