Question

the voltage in a light - bulb is given by the equation v = ir. in this equation, v is the voltage, i is the current, and r is the resistance. what is the current in a light - bulb with a voltage of 35.0 v and a resistance of 175 ω?
a. 0.200 a
b. 1.40 a
c. 6125 a
d. 5.00 a

Explanation:

Step1: Rearrange the formula for current

Given $V = IR$, we can solve for $I$ by dividing both sides by $R$, so $I=\frac{V}{R}$.

Step2: Substitute the given values

We have $V = 35.0\ V$ and $R=175\ \Omega$. Substituting into the formula $I=\frac{35.0}{175}$.

Step3: Calculate the value of current

$I = 0.200\ A$.

Answer:

A. 0.200 A