Question

welcome to math challenge #9. this challenge invites you into the world of shopping will use coins and dollars to solve real - life math problems. building on what you prac challenge 8, you will add prices, calculate the correct amount of change, compare co decide which deals are better. these challenges will ask you to organize information, smart strategies, and clearly explain your thinking—just like a careful shopper using day.
kinder & first grade: solve at least 3 problems.
second & third grade: solve at least 7 problems.
fourth grade and above: solve at least 12 problems.

1. inside michelle’s coin purse, there are only 5 pennies and 2 dimes. how much money does michelle have in her coin’s purse?
2. liz bought a lollipop using exactly 5 nickels. how much did the lollipop cost?
3. at a snack shop:

• a cookie costs 20¢
• a juice box costs 30¢

ben buys one cookie and one juice box. he pays with two quarters (25¢ each). how much change should he receive?

1. a toy costs 35¢. mia has two quarters (25¢ each) to spend. after buying the toy, how much money will she have left?
2. leo bought an apple for 40 cents. he paid with a $1.00 bill (100 cents), and he received 3 coins back from the cashier. what were the three coins he received?

Explanation:

Problem 1:

Step1: Calculate value of pennies

1 penny = 1 cent, so 5 pennies = \( 5 \times 1 = 5 \) cents.

Step2: Calculate value of dimes

1 dime = 10 cents, so 2 dimes = \( 2 \times 10 = 20 \) cents.

Step3: Total money

Total = pennies + dimes = \( 5 + 20 = 25 \) cents.

Step1: Value of one nickel

1 nickel = 5 cents.

Step2: Total cost for 5 nickels

Total cost = \( 5 \times 5 = 25 \) cents.

Step1: Total cost of items

Cookie (20¢) + Juice box (30¢) = \( 20 + 30 = 50 \) cents.

Step2: Total money paid

2 quarters, 1 quarter = 25¢, so total paid = \( 2 \times 25 = 50 \) cents.

Step3: Calculate change

Change = Paid - Cost = \( 50 - 50 = 0 \) cents.

Answer:

25 cents

Problem 2: