Question

7 what was the average temperature for the month of april in washington d.c.? daily average temperature (°f), washington d.c. (april 2010)
stem | leaf
5 | 3, 5, 3, 5, 9, 8, 0, 6, 8, 5, 9, 8, 6, 2, 8
6 | 0, 5, 1, 6, 9, 1, 4, 2, 3, 5, 6
7 | 6, 7, 0, 1
source: national weather service forecast office... monthly climate data, bruegel national, april 2010?
options: 69 degrees, 59 degrees, 61 degrees, 65 degrees.
skip 6/10 complete

Explanation:

Step1: Count number of data points

For stem 5: Let's count the leaves. The leaves are 3,5,3,5,9,8,0,6,8,5,9,8,6,2,8. Let's count them: 15 values.
For stem 6: Leaves are 0,5,1,6,9,1,4,2,3,5,6. Count: 11 values.
For stem 7: Leaves are 6,7,0,1. Count: 4 values.
Total number of days in April (data points) = 15 + 11 + 4 = 30.

Step2: Calculate total temperature for stem 5

Stem 5 means the tens place is 5, so each leaf is the ones place.
Sum of leaves for stem 5:
3 + 5 + 3 + 5 + 9 + 8 + 0 + 6 + 8 + 5 + 9 + 8 + 6 + 2 + 8
Let's calculate step by step:
3+5=8; 8+3=11; 11+5=16; 16+9=25; 25+8=33; 33+0=33; 33+6=39; 39+8=47; 47+5=52; 52+9=61; 61+8=69; 69+6=75; 75+2=77; 77+8=85.
Total for stem 5: 5015 + 85? Wait, no. Wait, stem 5: each data point is 50 + leaf. So sum for stem 5: 1550 + sum(leaves). Sum(leaves)=85. So 15*50 = 750; 750 + 85 = 835.

Step3: Calculate total temperature for stem 6

Stem 6: each data point is 60 + leaf.
Sum of leaves for stem 6: 0 + 5 + 1 + 6 + 9 + 1 + 4 + 2 + 3 + 5 + 6.
Calculate: 0+5=5; 5+1=6; 6+6=12; 12+9=21; 21+1=22; 22+4=26; 26+2=28; 28+3=31; 31+5=36; 36+6=42.
Sum for stem 6: 11*60 + 42 = 660 + 42 = 702.

Step4: Calculate total temperature for stem 7

Stem 7: each data point is 70 + leaf.
Sum of leaves for stem 7: 6 + 7 + 0 + 1 = 14.
Sum for stem 7: 4*70 + 14 = 280 + 14 = 294.

Step5: Calculate total sum and average

Total sum = 835 (stem5) + 702 (stem6) + 294 (stem7) = 835 + 702 = 1537; 1537 + 294 = 1831.
Average = total sum / number of data points = 1831 / 30 ≈ 61.03, which is approximately 61 degrees.

Answer:

61 degrees