Question

what is the concentration in parts per million of ddt in each of the following?part 1 of 20.029 mg in 1600. g plankton. be sure your answer has the correct number of significant figures.note: reference the si prefixes table for additional information.ppm ddt

Explanation:

Step1: Convert mass units to match

Since 1 g = 1000 mg, convert 1600. g to mg:
$1600. \text{ g} \times 1000 = 1.600 \times 10^6 \text{ mg}$

Step2: Calculate ppm concentration

ppm is $\frac{\text{mass of solute}}{\text{mass of solution}} \times 10^6$. Substitute values:
$\text{ppm} = \frac{0.029 \text{ mg}}{1.600 \times 10^6 \text{ mg}} \times 10^6$

Step3: Simplify and apply sig figs

Cancel $10^6$, compute the ratio:
$\frac{0.029}{1.600} = 0.018125$
Round to 2 significant figures (from 0.029):
$0.018$

Answer:

0.018 ppm DDT