Question

2.) what is the correct ionic formula for chromium (ii) iodide?
○ $\ce{cr_{2}i_{2}}$
○ $\ce{cri_{2}}$
○ $\ce{cr_{2}i}$
○ $\ce{cri}$

Explanation:

Step1: Determine ion charges

Chromium (II) has a charge of \( \text{Cr}^{2+} \), iodide (iodine ion) has a charge of \( \text{I}^- \).

Step2: Balance charges

To balance the charges, we need 2 iodide ions (\( 2\times(-1) = -2 \)) to balance 1 chromium (II) ion (\( +2 \)). So the formula is \( \text{CrI}_2 \).

Answer:

B. \( \text{CrI}_2 \) (assuming the second option is \( \text{CrI}_2 \))