Question

what is the molar mass of the following compounds? (5 points each)
fe₂o₃
h₃po₄
febr₃
c₂h₅oh

Explanation:

For $\boldsymbol{Fe_2O_3}$:

Step1: Identify atomic masses

Atomic mass of Fe = $55.85\ g/mol$, O = $16.00\ g/mol$.

Step2: Calculate total mass for each element

Fe: $2\times55.85 = 111.7\ g/mol$; O: $3\times16.00 = 48.00\ g/mol$.

Step3: Sum the masses

Molar mass = $111.7 + 48.00 = 159.7\ g/mol$.

For $\boldsymbol{H_3PO_4}$:

Step1: Identify atomic masses

H = $1.01\ g/mol$, P = $30.97\ g/mol$, O = $16.00\ g/mol$.

Step2: Calculate total mass for each element

H: $3\times1.01 = 3.03\ g/mol$; P: $1\times30.97 = 30.97\ g/mol$; O: $4\times16.00 = 64.00\ g/mol$.

Step3: Sum the masses

Molar mass = $3.03 + 30.97 + 64.00 = 98.00\ g/mol$.

For $\boldsymbol{FeBr_3}$:

Step1: Identify atomic masses

Fe = $55.85\ g/mol$, Br = $79.90\ g/mol$.

Step2: Calculate total mass for each element

Fe: $1\times55.85 = 55.85\ g/mol$; Br: $3\times79.90 = 239.7\ g/mol$.

Step3: Sum the masses

Molar mass = $55.85 + 239.7 = 295.55\ g/mol$.

For $\boldsymbol{C_2H_5OH}$ (or $\boldsymbol{C_2H_6O}$):

Answer:

s:

• $Fe_2O_3$: $\boldsymbol{159.7\ g/mol}$ (or $160\ g/mol$ approximately)
• $H_3PO_4$: $\boldsymbol{98.00\ g/mol}$
• $FeBr_3$: $\boldsymbol{295.55\ g/mol}$ (or $296\ g/mol$ approximately)
• $C_2H_5OH$: $\boldsymbol{46.08\ g/mol}$ (or $46\ g/mol$ approximately)