Question

what is the h⁺ in a solution that has a ph of 3.35?

a. 1 × 10^3.35 m
b. 2.2 × 10^3 m
c. 4.5 × 10^-4 m
d. 3.35 × 10^-14 m
e. the ph changes to 7.8

Explanation:

Step1: Recall pH formula

The formula relating pH and hydrogen ion concentration \([H^+]\) is \(pH = -\log_{10}[H^+]\). To find \([H^+]\), we can rearrange this formula to \([H^+]=10^{-pH}\).

Step2: Substitute pH value

Given \(pH = 3.35\), substitute into the formula: \([H^+]=10^{- 3.35}\).
Calculate \(10^{-3.35}\). We know that \(10^{-3.35}=10^{-3 - 0.35}=10^{-3}\times10^{-0.35}\). \(10^{-0.35}\approx0.447\), so \(10^{-3}\times0.447 = 4.47\times10^{-4}\approx4.5\times10^{-4}\space M\).

Answer:

c. \(4.5\times 10^{-4}\space M\)