Question

what volume of 18.0 m h₂so₄ is needed to make 0.900 l of a 6.00 m solution? (hint: m₁v₁ = m₂v₂)
1.00 l
0.300 l
0.100 l
5.00 l
0.900 l

Explanation:

Step1: Identify given values

$M_1 = 18.0\ M$, $V_2=0.900\ L$, $M_2 = 6.00\ M$

Step2: Rearrange the dilution formula

From $M_1V_1 = M_2V_2$, we can solve for $V_1$ as $V_1=\frac{M_2V_2}{M_1}$

Step3: Substitute values

$V_1=\frac{6.00\ M\times0.900\ L}{18.0\ M}$
$V_1 = 0.300\ L$

Answer:

B. 0.300 L