Question

which compound is an exception to the octet rule?
h₂o
hcl
ccl₄
clf₃

Explanation:

duet rule, satisfied).

• $\ce{HCl}$: Cl has 7 valence e⁻, 1 from H: $7+1=8$; H has 2 e⁻ (satisfied).
• $\ce{CCl4}$: C has 4 valence e⁻, 4 from Cl: $4+4=8$; each Cl has $7+1=8$ e⁻.
• $\ce{ClF3}$: Cl has 7 valence e⁻, 3 from F: $7+3=10$ e⁻ (exceeds 8).

Step3: Identify the exception

$\ce{ClF3}$ has 10 valence e⁻ on Cl, violating octet rule.

Answer:

duet rule, satisfied).

• $\ce{HCl}$: Cl has 7 valence e⁻, 1 from H: $7+1=8$; H has 2 e⁻ (satisfied).
• $\ce{CCl4}$: C has 4 valence e⁻, 4 from Cl: $4+4=8$; each Cl has $7+1=8$ e⁻.
• $\ce{ClF3}$: Cl has 7 valence e⁻, 3 from F: $7+3=10$ e⁻ (exceeds 8).

Step3: Identify the exception

$\ce{ClF3}$ has 10 valence e⁻ on Cl, violating octet rule.