Question

which electron configuration represents a violation of the pauli exclusion principle? * (0.5 points) a) 1s: ↑, 2s: ↑↓, 2p: empty empty empty b) 1s: ↑↑, 2s: ↑↓, 2p: empty empty empty c) 1s: ↑↓, 2s: ↑↓, 2p: ↑↓ empty empty d) 1s: ↑↓, 2s: ↑↓, 2p: ↑ empty ↑ e) 1s: ↑, 2s: ↑, 2p: ↑ ↑ ↑ a b c d e

Explanation:

The Pauli Exclusion Principle states that no two electrons in an atom can have the same set of four quantum numbers, and in an orbital, there can be at most two electrons with opposite spins. In option B, the 1s orbital has two electrons with the same spin (both up - arrows), which violates the Pauli Exclusion Principle.

Answer:

B. 1s with two up - spin electrons, 2s with opposite - spin electrons, 2p empty