Question

which has higher tangential speed?

Explanation:

Step1: Recall tangential speed formula

The tangential speed \(v\) is given by \(v = \omega r\), where \(\omega\) is angular velocity, and \(r\) is the radius from the axis of rotation.

Step2: Analyze angular velocity

Points A and B are on the same rotating system, so they have equal angular velocity (\(\omega_A = \omega_B\)).

Step3: Compare radii

From the diagram, the radius of point B (\(r_B\)) is larger than the radius of point A (\(r_A\)), so \(r_B > r_A\).

Step4: Compare tangential speeds

Substitute into the formula: \(v_A = \omega r_A\), \(v_B = \omega r_B\). Since \(\omega\) is the same and \(r_B > r_A\), \(v_B > v_A\).

Answer:

Point B has a higher tangential speed.