QUESTION IMAGE
Question
which individual color(s) result in a probability of being selected? red as well as blue green blue as well as green yellow
Step1: Count total sections
There are 12 sections.
Step2: Count green sections
There are 4 green sections. Probability of green is $\frac{4}{12}=\frac{1}{3}$.
Step3: Count blue sections
There are 3 blue sections. Probability of blue is $\frac{3}{12}=\frac{1}{4}$.
Step4: Count red sections
There are 3 red sections. Probability of red is $\frac{3}{12}=\frac{1}{4}$.
Step5: Count yellow sections
There are 2 yellow sections. Probability of yellow is $\frac{2}{12}=\frac{1}{6}$.
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