Question

which statement concerning the compound shown below is incorrect? it is a tertiary alcohol. its molecular formula is c₆h₁₄o. its name is 2 - methyl - 2 - pentanol. it can be oxidized to give a ketone. it can form intermolecular hydrogen bonds.

Explanation:

Step1: Identify the alcohol type

The -OH group is attached to a carbon that is bonded to three other carbon - atoms, so it is a tertiary alcohol.

Step2: Determine the molecular formula

Counting the carbon, hydrogen, and oxygen atoms, there are 6 carbons, 14 hydrogens, and 1 oxygen, so the molecular formula is \(C_{6}H_{14}O\).

Step3: Name the compound

Using IUPAC rules, the longest carbon - chain has 5 carbons and there is a methyl group on the second carbon and the -OH group on the second carbon, so the name is 2 - methyl - 2 - pentanol.

Step4: Analyze oxidation

Tertiary alcohols cannot be oxidized to ketones or aldehydes under normal conditions because the carbon bearing the -OH group has no hydrogen atoms attached to it that can be lost during oxidation.

Step5: Consider hydrogen - bonding

Since it has an -OH group, it can form intermolecular hydrogen bonds.

Answer:

It can be oxidized to give a ketone.