Question

3 while an fm radio station broadcasts at a frequency of 94.7 mhz, an am station broadcast at a frequency of 829 khz. what is the wavelength of the am broadcast? * (0.5 points) 5.29 x 10^(-31) m 3.61 x 10^5 m 2.76 x 10^(-3) m 2.75 x 10^(-6) m 362 m 3.62 x 10^5 m

Explanation:

Step1: Recall the wave - speed formula

The speed of an electromagnetic wave is given by $c = \lambda f$, where $c$ is the speed of light ($c=3\times 10^{8}\ m/s$), $\lambda$ is the wavelength, and $f$ is the frequency. We need to solve for $\lambda$, so $\lambda=\frac{c}{f}$.

Step2: Convert the AM - station frequency to Hz

The AM station broadcasts at a frequency of $f = 829\ kHz=829\times10^{3}\ Hz$.

Step3: Calculate the wavelength

Substitute $c = 3\times 10^{8}\ m/s$ and $f = 829\times 10^{3}\ Hz$ into the formula $\lambda=\frac{c}{f}$.
$\lambda=\frac{3\times 10^{8}\ m/s}{829\times 10^{3}\ Hz}\approx362\ m$.

Answer:

$362\ m$