Question

write a balanced chemical equation based on the following description: c₆h₁₄ gas reacts with oxygen gas to produce carbon dioxide gas and water vapor c₆h₁₄(g) + o₂(g)→

Explanation:

Step1: Write the un - balanced products

The products of the combustion of $C_6H_{14}$ are $CO_2$ and $H_2O$. So the un - balanced equation is $C_6H_{14}(g)+O_2(g)
ightarrow CO_2(g)+H_2O(g)$.

Step2: Balance carbon atoms

There are 6 carbon atoms in $C_6H_{14}$. So we put a coefficient of 6 in front of $CO_2$: $C_6H_{14}(g)+O_2(g)
ightarrow 6CO_2(g)+H_2O(g)$.

Step3: Balance hydrogen atoms

There are 14 hydrogen atoms in $C_6H_{14}$. So we put a coefficient of 7 in front of $H_2O$: $C_6H_{14}(g)+O_2(g)
ightarrow 6CO_2(g)+7H_2O(g)$.

Step4: Balance oxygen atoms

On the right - hand side, the total number of oxygen atoms is $6\times2 + 7\times1=12 + 7 = 19$. So we put a coefficient of $\frac{19}{2}$ in front of $O_2$: $C_6H_{14}(g)+\frac{19}{2}O_2(g)
ightarrow 6CO_2(g)+7H_2O(g)$.

Step5: Multiply through by 2 to get whole - number coefficients

$2C_6H_{14}(g)+19O_2(g)
ightarrow 12CO_2(g)+14H_2O(g)$.

Answer:

$2C_6H_{14}(g)+19O_2(g)
ightarrow 12CO_2(g)+14H_2O(g)$