Question

write the balanced dissociation equation for solid aluminum sulfide in aqueous solution. if it does not dissociate, simply write only nr. be sure to include the proper phases for all species within the reaction.

Explanation:

Step1: Identify the formula of aluminum sulfide

Aluminum has a +3 charge ($Al^{3 + }$) and sulfide has a - 2 charge ($S^{2-}$). The formula of aluminum sulfide is $Al_2S_3$.

Step2: Write the dissociation equation

When $Al_2S_3$ dissociates in aqueous solution, it breaks into its constituent ions. The balanced dissociation equation is $Al_2S_3(s)
ightarrow2Al^{3 + }(aq)+3S^{2 - }(aq)$.

Answer:

$Al_2S_3(s)
ightarrow2Al^{3 + }(aq)+3S^{2 - }(aq)$