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writing formulas ( criss-cross method)directions: write the formulas of…

Question

writing formulas ( criss-cross method)directions: write the formulas of the compounds produced from the listed ions.$f^-$ $o^{2-}$ $n^{3-}$ $s^{2-}$ $so4^{2-}$$fe^{3+}$$zn^{2+}$$mg^{2+}$$na^+$$al^{3+}$

Explanation:

Step1: Criss-cross charges for $\text{Fe}^{3+}$

  • With $\text{F}^-$: $\text{Fe}^{3+}$ and $\text{F}^-$ → $\text{FeF}_3$
  • With $\text{O}^{2-}$: $\text{Fe}^{3+}$ and $\text{O}^{2-}$ → $\text{Fe}_2\text{O}_3$
  • With $\text{N}^{3-}$: $\text{Fe}^{3+}$ and $\text{N}^{3-}$ → $\text{FeN}$
  • With $\text{S}^{2-}$: $\text{Fe}^{3+}$ and $\text{S}^{2-}$ → $\text{Fe}_2\text{S}_3$
  • With $\text{SO}_4^{2-}$: $\text{Fe}^{3+}$ and $\text{SO}_4^{2-}$ → $\text{Fe}_2(\text{SO}_4)_3$

Step2: Criss-cross charges for $\text{Zn}^{2+}$

  • With $\text{F}^-$: $\text{Zn}^{2+}$ and $\text{F}^-$ → $\text{ZnF}_2$
  • With $\text{O}^{2-}$: $\text{Zn}^{2+}$ and $\text{O}^{2-}$ → $\text{ZnO}$
  • With $\text{N}^{3-}$: $\text{Zn}^{2+}$ and $\text{N}^{3-}$ → $\text{Zn}_3\text{N}_2$
  • With $\text{S}^{2-}$: $\text{Zn}^{2+}$ and $\text{S}^{2-}$ → $\text{ZnS}$
  • With $\text{SO}_4^{2-}$: $\text{Zn}^{2+}$ and $\text{SO}_4^{2-}$ → $\text{ZnSO}_4$

Step3: Criss-cross charges for $\text{Mg}^{2+}$

  • With $\text{F}^-$: $\text{Mg}^{2+}$ and $\text{F}^-$ → $\text{MgF}_2$
  • With $\text{O}^{2-}$: $\text{Mg}^{2+}$ and $\text{O}^{2-}$ → $\text{MgO}$
  • With $\text{N}^{3-}$: $\text{Mg}^{2+}$ and $\text{N}^{3-}$ → $\text{Mg}_3\text{N}_2$
  • With $\text{S}^{2-}$: $\text{Mg}^{2+}$ and $\text{S}^{2-}$ → $\text{MgS}$
  • With $\text{SO}_4^{2-}$: $\text{Mg}^{2+}$ and $\text{SO}_4^{2-}$ → $\text{MgSO}_4$

Step4: Criss-cross charges for $\text{Na}^+$

  • With $\text{F}^-$: $\text{Na}^+$ and $\text{F}^-$ → $\text{NaF}$
  • With $\text{O}^{2-}$: $\text{Na}^+$ and $\text{O}^{2-}$ → $\text{Na}_2\text{O}$
  • With $\text{N}^{3-}$: $\text{Na}^+$ and $\text{N}^{3-}$ → $\text{Na}_3\text{N}$
  • With $\text{S}^{2-}$: $\text{Na}^+$ and $\text{S}^{2-}$ → $\text{Na}_2\text{S}$
  • With $\text{SO}_4^{2-}$: $\text{Na}^+$ and $\text{SO}_4^{2-}$ → $\text{Na}_2\text{SO}_4$

Step5: Criss-cross charges for $\text{Al}^{3+}$

  • With $\text{F}^-$: $\text{Al}^{3+}$ and $\text{F}^-$ → $\text{AlF}_3$
  • With $\text{O}^{2-}$: $\text{Al}^{3+}$ and $\text{O}^{2-}$ → $\text{Al}_2\text{O}_3$
  • With $\text{N}^{3-}$: $\text{Al}^{3+}$ and $\text{N}^{3-}$ → $\text{AlN}$
  • With $\text{S}^{2-}$: $\text{Al}^{3+}$ and $\text{S}^{2-}$ → $\text{Al}_2\text{S}_3$
  • With $\text{SO}_4^{2-}$: $\text{Al}^{3+}$ and $\text{SO}_4^{2-}$ → $\text{Al}_2(\text{SO}_4)_3$

Answer:

$\text{F}^-$$\text{O}^{2-}$$\text{N}^{3-}$$\text{S}^{2-}$$\text{SO}_4^{2-}$
$\text{Zn}^{2+}$$\text{ZnF}_2$$\text{ZnO}$$\text{Zn}_3\text{N}_2$$\text{ZnS}$$\text{ZnSO}_4$
$\text{Mg}^{2+}$$\text{MgF}_2$$\text{MgO}$$\text{Mg}_3\text{N}_2$$\text{MgS}$$\text{MgSO}_4$
$\text{Na}^+$$\text{NaF}$$\text{Na}_2\text{O}$$\text{Na}_3\text{N}$$\text{Na}_2\text{S}$$\text{Na}_2\text{SO}_4$
$\text{Al}^{3+}$$\text{AlF}_3$$\text{Al}_2\text{O}_3$$\text{AlN}$$\text{Al}_2\text{S}_3$$\text{Al}_2(\text{SO}_4)_3$