Question

question 13 (0.25 points)listenwhat is the identity of the ion with an electron configuration of ar $3d^{10}$ and has a charge of +3?$ce{sc^{3+}}LXB0ce{p^{3+}}LXB1ce{zr^{4+}}LXB2ce{ru^{4+}}$

Explanation:

Step1: Find neutral atom e⁻ count (Q13)

Ion e⁻ count = Ar electrons + 10 = 18 + 10 = 28. Neutral atom e⁻ = 28 + 3 = 31.

Step2: Match atomic number (Q13)

Atomic number 31 corresponds to Ga, so ion is $\text{Ga}^{3+}$.

Step3: Find neutral atom e⁻ count (Q14)

Ion e⁻ count = Kr electrons + 10 = 36 + 10 = 46. Neutral atom e⁻ = 46 + 4 = 50.

Step4: Match atomic number (Q14)

Atomic number 50 corresponds to Sn, so ion is $\text{Sn}^{4+}$.

Answer:

Question 13: B. $\text{Ga}^{3+}$
Question 14: A. $\text{Sn}^{4+}$