Question

temperature (18 pts.)
7.

	°c	°f	k
room temperature
ice water
boiling water

1. how well do your thermometer readings agree with the accepted values for the freezing point and boiling point of water? express any discrepancy as a deviation in degrees. (5 pts.)

Explanation:

Question 7: Filling the Temperature Table

Step 1: Recall Temperature Conversion Formulas

• Celsius to Fahrenheit: \( ^\circ\text{F} = \frac{9}{5}^\circ\text{C} + 32 \)
• Celsius to Kelvin: \( \text{K} = ^\circ\text{C} + 273.15 \)

Step 2: Room Temperature (Typical Values)

• \( ^\circ\text{C} \approx 25 \)
• \( ^\circ\text{F} = \frac{9}{5}(25) + 32 = 45 + 32 = 77 \)
• \( \text{K} = 25 + 273.15 = 298.15 \)

Step 3: Ice Water (Freezing Point of Water)

• \( ^\circ\text{C} = 0 \)
• \( ^\circ\text{F} = \frac{9}{5}(0) + 32 = 32 \)
• \( \text{K} = 0 + 273.15 = 273.15 \)

Step 4: Boiling Water (Boiling Point of Water)

• \( ^\circ\text{C} = 100 \)
• \( ^\circ\text{F} = \frac{9}{5}(100) + 32 = 180 + 32 = 212 \)
• \( \text{K} = 100 + 273.15 = 373.15 \)

Question 8: Analyzing Thermometer Readings

1. Accepted Values:

• Freezing point of water: \( 0^\circ\text{C} \) (or \( 32^\circ\text{F} \), \( 273.15\text{K} \))
• Boiling point of water: \( 100^\circ\text{C} \) (or \( 212^\circ\text{F} \), \( 373.15\text{K} \))

1. Deviation Calculation:

Deviation = \( |\text{Measured Value} - \text{Accepted Value}| \).
For example, if a thermometer reads \( 2^\circ\text{C} \) for ice water, the deviation is \( |2 - 0| = 2^\circ\text{C} \).

Final Answers

Question 7 Table:

	\( ^\circ\text{C} \)	\( ^\circ\text{F} \)	\( \text{K} \)
Ice Water	0	32	273.15
Boiling Water	100	212	373.15

Question 8:

To determine agreement, calculate the absolute difference between measured and accepted values (e.g., if ice water reads \( T_{\text{measured}} \), deviation = \( |T_{\text{measured}} - 0^\circ\text{C}| \) for Celsius, or similar for other scales). Report deviations in degrees (e.g., "My ice water reading deviated by \( 1^\circ\text{C} \) from \( 0^\circ\text{C} \), and boiling water deviated by \( 0.5^\circ\text{C} \) from \( 100^\circ\text{C} \)").

Answer:

1. Accepted Values:

• Freezing point of water: \( 0^\circ\text{C} \) (or \( 32^\circ\text{F} \), \( 273.15\text{K} \))
• Boiling point of water: \( 100^\circ\text{C} \) (or \( 212^\circ\text{F} \), \( 373.15\text{K} \))

1. Deviation Calculation:

Deviation = \( |\text{Measured Value} - \text{Accepted Value}| \).
For example, if a thermometer reads \( 2^\circ\text{C} \) for ice water, the deviation is \( |2 - 0| = 2^\circ\text{C} \).

Final Answers

Question 7 Table:

	\( ^\circ\text{C} \)	\( ^\circ\text{F} \)	\( \text{K} \)
Ice Water	0	32	273.15
Boiling Water	100	212	373.15

Question 8:

To determine agreement, calculate the absolute difference between measured and accepted values (e.g., if ice water reads \( T_{\text{measured}} \), deviation = \( |T_{\text{measured}} - 0^\circ\text{C}| \) for Celsius, or similar for other scales). Report deviations in degrees (e.g., "My ice water reading deviated by \( 1^\circ\text{C} \) from \( 0^\circ\text{C} \), and boiling water deviated by \( 0.5^\circ\text{C} \) from \( 100^\circ\text{C} \)").