Question

which statement best describes the formula equation $\ce{cl_2(g) + 2kbr(aq) -> 2kcl(aq) + br_2(l)}$?

• carbon iodide reacts with potassium bromide to form potassium carbon iodide and bromine.
• bromine gas reacts with a solution of potassium chloride to form potassium bromide and chlorine gas.
• potassium bromine gas reacts with liquid chlorine to form potassium chloride in solution and bromine gas.
• chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromine.

Explanation:

1. Analyze the reactants and products from the chemical equation $\ce{Cl_{2}(g) + 2KBr(aq) \to 2KCl(aq) + Br_{2}(l)}$:

• Reactants: Chlorine gas ($\ce{Cl_{2}(g)}$) and potassium bromide ($\ce{KBr(aq)}$).
• Products: Potassium chloride ($\ce{KCl(aq)}$) and liquid bromide ($\ce{Br_{2}(l)}$).

1. Evaluate each option:

• First option: Incorrect reactants (mentions carbon iodide, which is not in the equation).
• Second option: Incorrect reactants (bromine gas is a product, not a reactant; potassium chloride is a product, not a reactant).
• Third option: Incorrect reactants (potassium bromine gas is not a valid species, and chlorine is gas, not liquid here).
• Fourth option: Correctly identifies reactants (chlorine gas, potassium bromide) and products (potassium chloride in solution, liquid bromine) as per the equation.

Answer:

D. Chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromine.