Question

1. mark the following with p for pny.

a. _p_ crumpled paper
b. _c_ burning paper
c. _c_ freezing water
d. _p_ frying an egg
e. _p_ raking
f. _c_ burning gasoline
g. _p_ cutting paper
h. _p_ adding iodine to starch, turning liquid

1. which of the following are physical properties? check all that apply.

□ boiling point
■ density
■ melting point
□ ability to corrode
□ temperature
□ flammability

1. if an object has a mass of 30 grams and a volume of 2 ml. what is its density?

a) 25 g/ml
b. 2.5 g/ml
c. 0.4 g/ml
d. 15 g/ml

1. place the following items into the correct columns of either a homogeneous, or heterogeneous mixture. there may not be an even number of each type.

• chocolate chip cookie
• pure water
• salt water
• dirty pond water
• vegetable soup
• unsweet tea
• salad
• saline solution

homogenous mixture | heterogenous mixture
chocolate chip | pure water
salt water | vegetable soup
dirty pond water | unsweet tea
salad |
saline solution |

1. a. an initial reading on a graduated cylinder is 50.0 ml of water. a block is added into the cylinder and the new volume is now 56.3ml. what is the volume of the block? ____________

b. if the mass of this block is 12.6 grams, what is the density of this block? show your work!!!

Explanation:

Step1: Recall density formula

The formula for density is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume.

Step2: Solve for question 12

Given $m = 30$ g and $V=2$ mL. Substitute into the formula: $
ho=\frac{30}{2}=15$ g/mL. So the answer to 12 is d.

Step3: Find volume of block in 14a

The volume of the block is the difference in the volume readings of the graduated - cylinder. $V_{block}=V_{final}-V_{initial}=56.3 - 50.0=6.3$ mL.

Step4: Solve for density of block in 14b

Given $m = 12.6$ g and $V = 6.3$ mL. Using the density formula $
ho=\frac{m}{V}=\frac{12.6}{6.3}=2$ g/mL.

For question 10:

• Physical changes (P): crumpled paper, raking, cutting paper
• Chemical changes (C): burning paper, burning gasoline, frying an egg, adding iodine to starch

For question 11:
Physical properties are characteristics that can be observed without changing the substance's chemical composition. Boiling point, density, melting point, and temperature are physical properties. The ability to corrode and flammability are chemical properties. So the answers are Boiling Point, Density, Melting Point, Temperature.

For question 13:

• Homogeneous mixtures: pure water, salt water, unsweet tea, saline solution
• Heterogeneous mixtures: chocolate - chip cookie, dirty pond water, vegetable soup, salad

Answer:

1. Physical changes (P): A, E, G; Chemical changes (C): B, F, D, H
2. Boiling Point, Density, Melting Point, Temperature
3. d. 15 g/mL
4. Homogeneous mixture: pure water, salt water, unsweet tea, saline solution; Heterogeneous mixture: chocolate - chip cookie, dirty pond water, vegetable soup, salad
5. a. 6.3 mL

b. 2 g/mL