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10/9 do now draw the atomic structure of $^{15}_{7}n$

Question

10/9
do now
draw the atomic structure of
$^{15}_{7}n$

Explanation:

Step1: Identify atomic number and mass number

The atomic number ($Z$) of nitrogen ($N$) is 7 and the mass number ($A$) is 15 as indicated by $_7^{15}N$.

Step2: Determine number of sub - atomic particles

The number of protons ($p$) is equal to the atomic number, so $p = 7$. The number of neutrons ($n$) is $n=A - Z=15 - 7 = 8$. The number of electrons ($e$) in a neutral atom is equal to the number of protons, so $e = 7$.

Step3: Draw the atomic structure

Draw a nucleus in the center. Write 7 protons and 8 neutrons inside the nucleus. Then, draw electron - shells around the nucleus. The first shell can hold a maximum of 2 electrons and the second shell can hold a maximum of 8 electrons. For nitrogen with 7 electrons, there are 2 electrons in the first shell and 5 electrons in the second shell.

Answer:

Draw a nucleus with 7 protons and 8 neutrons. Surround it with two electron - shells: the first shell has 2 electrons and the second shell has 5 electrons.