Question

1. a) barium metal is in group-2 (or iia).what type of ion will it form as it is a metal.

b)what will be the sign of charge (and how much charge) on it when it forms the above type of ion??

c)what was the original number of total electrons it had (together from valence electrons and inner electrons)?

d)what will be the new number of electrons the ion is formed?

Explanation:

Part (a)

Step1: Recall Group 2 metal ion formation

Group 2 (IIA) metals have 2 valence electrons. Metals lose valence electrons to form cations (positive ions) to achieve a stable electron configuration (like a noble gas). So barium, being a Group 2 metal, will lose its 2 valence electrons and form a cation.

Step1: Determine charge sign and magnitude

Group 2 metals lose 2 electrons. Electrons are negatively charged, so losing electrons means the ion has more protons (positive charge) than electrons. So the charge is positive, and the magnitude is 2 (since it loses 2 electrons).

Step1: Find barium's atomic number

Barium (Ba) has an atomic number of 56. In a neutral atom, the number of electrons equals the atomic number (since protons = electrons in neutral atoms). So the original number of electrons is equal to its atomic number, 56.

Answer:

Cation (specifically \( \text{Ba}^{2+} \) - but the type is cation)

Part (b)