Question

1. calcium hydroxide + phosphoric acid → water + calcium phosphate
2. barium chloride + sodium carbonate → barium carbonate + sodium chloride
3. zinc + nickel(ii) nitrate → zinc nitrate + nickel
4. antimony + iodine → antimony(iii) iodide
5. carbon dioxide → carbon + oxygen
6. iron(iii) sulphate + lead → lead(ii) sulphate + iron
7. barium nitrate + ammonium carbonate → ammonium nitrate + barium carbonate
8. zinc hydroxide + hydrochloric acid → water + zinc chloride
9. ammonium carbonate + magnesium chloride → ammonium chloride + magnesium carbonate
10. rubidium hydroxide + sulphuric acid → water + rubidium sulphate

Explanation:

Step1: Write formulas for reactants/products

Identify chemical formulas (e.g., calcium hydroxide = $\text{Ca(OH)}_2$).

Step2: Balance atoms

Adjust coefficients to equalize atom counts on both sides (e.g., 3 $\text{Ca(OH)}_2$ balances Ca).

Step3: Verify balance

Check all elements for equal numbers (e.g., O, H in reaction 11).
Repeat for each reaction.

Answer:

1. $3\text{Ca(OH)}_2 + 2\text{H}_3\text{PO}_4

ightarrow 6\text{H}_2\text{O} + \text{Ca}_3(\text{PO}_4)_2$

1. $\text{BaCl}_2 + \text{Na}_2\text{CO}_3

ightarrow \text{BaCO}_3 + 2\text{NaCl}$

1. $\text{Zn} + \text{Ni(NO}_3\text{)}_2

ightarrow \text{Zn(NO}_3\text{)}_2 + \text{Ni}$

1. $2\text{Sb} + 3\text{I}_2

ightarrow 2\text{SbI}_3$

1. $\text{CO}_2

ightarrow \text{C} + \text{O}_2$

1. $2\text{Fe}_2(\text{SO}_4)_3 + 6\text{Pb}

ightarrow 6\text{PbSO}_4 + 4\text{Fe}$

1. $\text{Ba(NO}_3\text{)}_2 + (\text{NH}_4\text{)}_2\text{CO}_3

ightarrow 2\text{NH}_4\text{NO}_3 + \text{BaCO}_3$

1. $\text{Zn(OH)}_2 + 2\text{HCl}

ightarrow 2\text{H}_2\text{O} + \text{ZnCl}_2$

1. $(\text{NH}_4\text{)}_2\text{CO}_3 + \text{MgCl}_2

ightarrow 2\text{NH}_4\text{Cl} + \text{MgCO}_3$

1. $2\text{RbOH} + \text{H}_2\text{SO}_4

ightarrow 2\text{H}_2\text{O} + \text{Rb}_2\text{SO}_4$