Question

1. which of the following formulas contains the fewest oxygen atoms? (1pts) ☐ al(c₂h₃o₂)₃ ☐ al₂(co₃)₃ ☐ k₂cr₂o₇ ☐ mg(mno₄)₂

Explanation:

Step1: Count O atoms in Option A

Each $\text{C}_2\text{H}_3\text{O}_2^-$ has 2 O, times 3: $2 \times 3 = 6$

Step2: Count O atoms in Option B

Each $\text{CO}_3^{2-}$ has 3 O, times 3: $3 \times 3 = 9$

Step3: Count O atoms in Option C

The formula has 7 O atoms directly: $7$

Step4: Count O atoms in Option D

Each $\text{MnO}_4^-$ has 4 O, times 2: $4 \times 2 = 8$

Step5: Compare all O counts

$6 < 7 < 8 < 9$

Answer:

A. $\text{Al(C}_2\text{H}_3\text{O}_2\text{)}_3$