Question

13-14. solid substance a has a melting point of 100°c. liquid substance b has a freezing point of 110°c. for each substance, identify its state of matter and describe the motion of the particles at 115°c
substance a at 115°c | substance b at 115°c
state: | state:
description: | description:

Explanation:

Substance A at 115°C

• State: Liquid
• Description: The temperature \( 115^\circ\text{C} \) is above substance A’s melting point (\( 100^\circ\text{C} \)), so it is liquid. In a liquid, particles are close together but can move past one another (sliding or flowing motion) as they have more kinetic energy than in a solid.

Substance B at 115°C

• State: Liquid
• Description: The temperature \( 115^\circ\text{C} \) is above substance B’s freezing point (\( 110^\circ\text{C} \))—since freezing point = melting point for a substance, \( 115^\circ\text{C} \) is above its melting point. Thus, it remains liquid. Liquid particles move by sliding/flowing past each other, with moderate kinetic energy (more than solids, less than gases).

Substance A at 115°C	Substance B at 115°C

Answer:

Substance A at 115°C

• State: Liquid
• Description: The temperature \( 115^\circ\text{C} \) is above substance A’s melting point (\( 100^\circ\text{C} \)), so it is liquid. In a liquid, particles are close together but can move past one another (sliding or flowing motion) as they have more kinetic energy than in a solid.

Substance B at 115°C

• State: Liquid
• Description: The temperature \( 115^\circ\text{C} \) is above substance B’s freezing point (\( 110^\circ\text{C} \))—since freezing point = melting point for a substance, \( 115^\circ\text{C} \) is above its melting point. Thus, it remains liquid. Liquid particles move by sliding/flowing past each other, with moderate kinetic energy (more than solids, less than gases).

Substance A at 115°C	Substance B at 115°C