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13. what is the mass of 1.0000 moles of ca(oh)₂?

Question

  1. what is the mass of 1.0000 moles of ca(oh)₂?

Explanation:

Step1: Find molar masses of elements

Molar mass of Ca: $40.08\ g/mol$, O: $16.00\ g/mol$, H: $1.008\ g/mol$.

Step2: Calculate molar mass of $\ce{Ca(OH)2}$

For $\ce{Ca(OH)2}$, there is 1 Ca, 2 O, and 2 H.
Molar mass = $40.08 + 2\times(16.00 + 1.008)$
= $40.08 + 2\times17.008$
= $40.08 + 34.016$
= $74.096\ g/mol$.

Step3: Relate moles to mass

Mass = moles × molar mass. For 1.0000 moles,
Mass = $1.0000\ mol\times74.096\ g/mol = 74.096\ g$.

Answer:

The mass of 1.0000 moles of $\ce{Ca(OH)2}$ is $\boldsymbol{74.096\ g}$ (or can be rounded appropriately, e.g., 74.10 g depending on precision needs).