QUESTION IMAGE
Question
- 15 g of four different solutes are added to four beakers, each containing 30 ml of water. the solute remaining after 2 minutes of agitation is removed from each of the beakers and weighed. which of the following solutions has the highest concentration?
| amount of water | initial amount of solute | final amount of solute | |
|---|---|---|---|
| substance b | 30 ml | 15 g | 5 g |
| substance c | 30 ml | 15 g | 15 g |
| substance d | 30 ml | 15 g | 0 g |
a. substance a
b. substance b
c. substance c
d. substance d
Step1: Recall concentration formula
Concentration = $\frac{\text{Mass of solute}}{\text{Volume of solution}}$. Here volume of water (and assuming volume of solution is same as volume of water for simplicity) is constant ($30$ mL) for all substances. So, higher the mass of solute remaining, higher the concentration.
Step2: Compare final solute masses
Substance A has 15 g of solute remaining, Substance B has 5 g, Substance C has 15 g and Substance D has 0 g. Since the mass of solute remaining for Substance A and Substance C is the highest among all.
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A. Substance A, C. Substance C