Question

1. how many electrons are found in the s - sublevel? 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰ a. 2 b. 4 c. 6 d. 8 16. which sublevel has the most electrons? 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶ a. s b. p c. d d. f count the electrons in each sublevel here... s = p = d = f =

Explanation:

Step1: Analyze s - subshell capacity

The s - subshell can hold a maximum of 2 electrons. In the electron - configuration $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}$, the s - subshells are 1s, 2s, 3s, 4s. Each s - subshell has 2 electrons, so the total number of electrons in s - subshells is $2 + 2+2 + 2=8$.

Step2: Count electrons in each sub - level for question 16

For the electron - configuration $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}$:

• For s - subshells: There are 5 s - subshells ($1s^{2},2s^{2},3s^{2},4s^{2},5s^{2}$), so the number of electrons in s - subshells is $2\times5 = 10$.
• For p - subshells: There are 3 p - subshells ($2p^{6},3p^{6},4p^{6},5p^{6}$), so the number of electrons in p - subshells is $6\times4=24$.
• For d - subshells: There are 3 d - subshells ($3d^{10},4d^{10}$), so the number of electrons in d - subshells is $10\times3 = 30$.
• There are no f - subshells in this electron - configuration. So the d - subshell has the most electrons.

Answer:

1. d. 8
2. c. d