Question

1. silicon, used in computer chips, has a heat capacity of 0.712 j g⁻¹ °c⁻¹. if 432 j of heat is absorbed by 8.16 g of silicon, what will the final temperature be if the initial temperature is 25.0°c? heat = mass × specific heat × δt, where δt = t_final - t_initial 49.4 °c 58.5 °c 99.4 °c 125 °c

Explanation:

Step1: Rearrange for $\Delta t$

$\Delta t = \frac{\text{heat}}{\text{mass} \times \text{specific heat}}$

Step2: Substitute given values

$\Delta t = \frac{432\ \text{J}}{8.16\ \text{g} \times 0.712\ \text{J g}^{-1} \degree\text{C}^{-1}} \approx 74.4\ \degree\text{C}$

Step3: Solve for final temperature

$t_{\text{final}} = \Delta t + t_{\text{initial}}$
$t_{\text{final}} = 74.4\ \degree\text{C} + 25.0\ \degree\text{C}$

Answer:

$\boldsymbol{99.4\ \degree\text{C}}$ (Option: $\square$ 99.4 °C)