Question

1. c₃h₈ + o₂ → co₂ + h₂o

Explanation:

Step1: Balance Carbon atoms

On the left, we have 3 C in \( \ce{C3H8} \). So, we put a coefficient of 3 in front of \( \ce{CO2} \) to balance C:
\( \ce{C3H8 + O2 -> 3CO2 + H2O} \)

Step2: Balance Hydrogen atoms

On the left, we have 8 H in \( \ce{C3H8} \). So, we put a coefficient of 4 in front of \( \ce{H2O} \) (since \( 4\times2 = 8 \)):
\( \ce{C3H8 + O2 -> 3CO2 + 4H2O} \)

Step3: Balance Oxygen atoms

On the right, total O is \( (3\times2) + (4\times1) = 6 + 4 = 10 \). So, we need 5 \( \ce{O2} \) (since \( 5\times2 = 10 \)):
\( \ce{C3H8 + 5O2 -> 3CO2 + 4H2O} \)

Answer:

\( \boldsymbol{\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}} \)