Question

1. provide 3 missing symbols and 2 numbers 16 n + 4 2 → 9 + 1 0

Explanation:

Step1: Analyze the left - hand side

We have \(^{16}_{N}\) and we know that in a nuclear reaction, the sum of mass numbers and atomic numbers on both sides must be equal. The mass number on the left - hand side is 16 and the atomic number of nitrogen is 7.

Step2: Analyze the right - hand side

The sum of mass numbers on the right - hand side should be 16 and the sum of atomic numbers should be 7. We have a particle with mass number 9 and atomic number 4 (beryllium, \(Be\)) and a particle with mass number 1 and atomic number 0 (neutron, \(n\)).

Step3: Determine the missing particle

Let the missing particle have mass number \(x\) and atomic number \(y\). Then \(x + 9+1=16\), so \(x = 6\), and \(y + 4 + 0=7\), so \(y = 3\). The element with atomic number 3 is lithium (\(Li\)).
The missing symbols and numbers make the reaction \(^{16}_{7}N+^{4}_{2}He
ightarrow^{9}_{4}Be + ^{6}_{3}Li+^{1}_{0}n\).
The three missing symbols are \(_{7}\), \(_{2}\), \(_{3}\) and the two missing numbers are 7, 3.

Answer:

The three missing symbols are \(_{7}\), \(_{2}\), \(_{3}\); the two missing numbers are 7, 3.