Question

1. ammonium hydroxide
2. barium sulfate
3. barium chloride
4. cobalt (ii) chloride
5. sodium carbonate
6. calcium oxide
7. lead (ii) nitrate
8. tin (ii) chloride

Explanation:

Step1: Write formula for ammonium hydroxide

Ammonium ion ($NH_4^+$) and hydroxide ion ($OH^-$) combine to form $NH_4OH$.

Step2: Write formula for barium sulfate

Barium ion ($Ba^{2 + }$) and sulfate ion ($SO_4^{2 - }$) combine to form $BaSO_4$.

Step3: Write formula for barium chloride

Barium ion ($Ba^{2+}$) and chloride ion ($Cl^-$), to balance charge we need 2 chloride ions, so formula is $BaCl_2$.

Step4: Write formula for cobalt (II) chloride

Cobalt (II) ion ($Co^{2+}$) and chloride ion ($Cl^-$), 2 chloride ions are needed for charge - balance, formula is $CoCl_2$.

Step5: Write formula for sodium carbonate

Sodium ion ($Na^+$) and carbonate ion ($CO_3^{2 - }$), 2 sodium ions are needed for charge - balance, formula is $Na_2CO_3$.

Step6: Write formula for calcium oxide

Calcium ion ($Ca^{2+}$) and oxide ion ($O^{2 - }$), formula is $CaO$.

Step7: Write formula for lead (II) nitrate

Lead (II) ion ($Pb^{2+}$) and nitrate ion ($NO_3^-$), 2 nitrate ions are needed for charge - balance, formula is $Pb(NO_3)_2$.

Step8: Write formula for tin (II) chloride

Tin (II) ion ($Sn^{2+}$) and chloride ion ($Cl^-$), 2 chloride ions are needed for charge - balance, formula is $SnCl_2$.

Answer:

1. $NH_4OH$
2. $BaSO_4$
3. $BaCl_2$
4. $CoCl_2$
5. $Na_2CO_3$
6. $CaO$
7. $Pb(NO_3)_2$
8. $SnCl_2$