Question

to 225 ml of a 0.80m solution of ki, a student adds enough water to make 1.0 l of a more dilute ki solution. what is the molarity of the new solution?
○ 0.18m
○ 2.8m
○ 0.35m
○ 180m

Explanation:

Step1: Define dilution formula

$M_1V_1 = M_2V_2$
Where $M_1=0.80M$, $V_1=225\ \text{mL}$, $V_2=1.0\ \text{L}=1000\ \text{mL}$, $M_2$ = final molarity.

Step2: Rearrange for $M_2$

$M_2 = \frac{M_1V_1}{V_2}$

Step3: Substitute values

$M_2 = \frac{0.80M \times 225\ \text{mL}}{1000\ \text{mL}} = 0.18M$

Answer:

0.18M