Question

6al₂(so₄)₃ al= s= o=

Explanation:

Step1: Calculate number of Al atoms

For one $Al_2(SO_4)_3$ unit, there are 2 Al atoms. With a coefficient of 6 in front of $Al_2(SO_4)_3$, the number of Al atoms is $6\times2 = 12$.

Step2: Calculate number of S atoms

In one $Al_2(SO_4)_3$ unit, there are 3 S atoms. With a coefficient of 6, the number of S atoms is $6\times3=18$.

Step3: Calculate number of O atoms

In one $Al_2(SO_4)_3$ unit, there are $4\times3 = 12$ O atoms. With a coefficient of 6, the number of O atoms is $6\times12 = 72$.

Answer:

$Al = 12$, $S = 18$, $O = 72$