al₂o₃ → al + o₂
cl₂ + nabr → nacl + br₂
h₂ + n₂ → nh₃
na + br₂ → nabr
cucl₂ + h₂s → cus + hcl
hgo + cl₂ → hgcl + o₂
c + h₂ → ch₄
kclo₃ → kcl + o₂
s₈ + f₂ → sf₆
bacl₂ + na₂so₄ → nacl + baso₄
for each reaction, determine rxn type: (each reaction has a rxn type blank to fill)

Question

Accepted Answer

### 1. $\ce{Al_{2}O_{3} -> Al + O_{2}}$
# Explanation:
## Step1: Identify reaction type
A single compound breaks down into simpler substances (Al and $\ce{O_{2}}$), so it's decomposition.
# Answer: Decomposition

### 2. $\ce{Cl_{2} + NaBr -> NaCl + Br_{2}}$
# Explanation:
## Step1: Identify reaction type
One element ($\ce{Cl_{2}}$) replaces another element (Br in $\ce{NaBr}$) in a compound, so it's single replacement.
# Answer: Single Replacement

### 3. $\ce{H_{2} + N_{2} -> NH_{3}}$
# Explanation:
## Step1: Identify reaction type
Two or more substances ($\ce{H_{2}}$ and $\ce{N_{2}}$) combine to form a single product ($\ce{NH_{3}}$), so it's synthesis.
# Answer: Synthesis

### 4. $\ce{Na + Br_{2} -> NaBr}$
# Explanation:
## Step1: Identify reaction type
Two substances (Na and $\ce{Br_{2}}$) combine to form a single product (NaBr), so it's synthesis.
# Answer: Synthesis

### 5. $\ce{CuCl_{2} + H_{2}S -> CuS + HCl}$
# Explanation:
## Step1: Identify reaction type
Ions of two compounds ($\ce{CuCl_{2}}$ and $\ce{H_{2}S}$) exchange places to form new compounds (CuS and HCl), so it's double replacement.
# Answer: Double Replacement

### 6. $\ce{HgO + Cl_{2} -> HgCl + O_{2}}$
# Explanation:
## Step1: Identify reaction type
A compound (HgO) breaks down, and there's also a replacement aspect, but mainly decomposition (HgO decomposes, and Cl₂ reacts, but the key is HgO breaking into Hg and O, with Cl₂ reacting with Hg). However, more accurately, it's a redox decomposition (but for basic types, decomposition as a compound breaks down, and also single replacement? Wait, no, let's re - check. The original HgO has Hg and O. Cl₂ reacts with Hg to form HgCl, and O is released as O₂. So it's a combination of decomposition (HgO → Hg + O₂) and single replacement (Hg + Cl₂ → HgCl). But maybe the main type here is decomposition (since HgO is breaking down). Wait, no, the reaction is HgO + Cl₂ → HgCl + O₂. So it's a redox reaction, but in terms of basic types, it's a decomposition - like (since a compound is breaking down) and also single replacement. But maybe the intended type is decomposition (as HgO is the reactant that's breaking into parts, with Cl₂ reacting with the Hg part). Alternatively, single replacement. But maybe the answer is decomposition (or redox, but basic types: decomposition).
# Answer: Decomposition (or Single Replacement, depending on interpretation, but likely decomposition as HgO is breaking down)

### 7. $\ce{C + H_{2} -> CH_{4}}$
# Explanation:
## Step1: Identify reaction type
Two substances (C and $\ce{H_{2}}$) combine to form a single product ($\ce{CH_{4}}$), so it's synthesis.
# Answer: Synthesis

### 8. $\ce{KClO_{3} -> KCl + O_{2}}$
# Explanation:
## Step1: Identify reaction type
A single compound ($\ce{KClO_{3}}$) breaks down into simpler substances (KCl and $\ce{O_{2}}$), so it's decomposition.
# Answer: Decomposition

### 9. $\ce{S_{8} + F_{2} -> SF_{6}}$
# Explanation:
## Step1: Identify reaction type
Two substances ($\ce{S_{8}}$ and $\ce{F_{2}}$) combine to form a single product ($\ce{SF_{6}}$), so it's synthesis.
# Answer: Synthesis

### 10. $\ce{BaCl_{2} + Na_{2}SO_{4} -> NaCl + BaSO_{4}}$
# Explanation:
## Step1: Identify reaction type
Ions of two compounds ($\ce{BaCl_{2}}$ and $\ce{Na_{2}SO_{4}}$) exchange places to form new compounds (NaCl and $\ce{BaSO_{4}}$), so it's double replacement.
# Answer: Double Replacement

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QUESTION IMAGE

Question

Explanation:

1. $\ce{Al_{2}O_{3} -> Al + O_{2}}$

Step1: Identify reaction type

Step1: Identify reaction type

Step1: Identify reaction type

Answer:

2. $\ce{Cl_{2} + NaBr -> NaCl + Br_{2}}$