Question

answer the questions about the following isotope $^{238}u^{+2}$. the atomic number, the number of protons, is 1. the mass number, the number of nucleons, is 2. the number of neutrons is 3. the number of electrons is 4. the charge is 5 making it an 6. a. 0 b. 1 c. 2 d. 3 e. 4 f. -1 g. -2 h. -3 i. -4 j. 238 k. 92 l. 90 m. 146 n. element o. anion p. cation

Explanation:

Step1: Identify element uranium

Uranium (U) has an atomic number of 92, which is the number of protons. So for the number of protons, the answer is 92 (K).

Step2: Determine mass number

The isotope is written as \(^{238}U^{+ 2}\), and the mass - number is 238 (J).

Step3: Calculate number of neutrons

Neutrons = Mass number - Atomic number. So, \(238−92 = 146\) (M).

Step4: Calculate number of electrons

The atom is a \(U^{+2}\) ion. A neutral uranium atom has 92 electrons. Since it has a + 2 charge, it has lost 2 electrons. So, \(92 - 2=90\) (L).

Step5: Determine charge

The ion is \(U^{+2}\), so the charge is + 2 (C).

Step6: Classify the ion

A positively - charged ion is a cation (P).

Answer:

1. K. 92
2. J. 238
3. M. 146
4. L. 90
5. C. 2
6. P. cation