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an atomic cation with a charge of + 1 has the following electron config…

Question

an atomic cation with a charge of + 1 has the following electron configuration ne 3s²3p¹. what is the chemical symbol for the ion? how many electrons does the ion have? how many 3p electrons are in the ion?

Explanation:

Step1: Determine the number of electrons in [Ne]

Neon ([Ne]) has 10 electrons.

Step2: Count electrons in 3s and 3p orbitals

The 3s² sub - shell has 2 electrons and the 3p¹ sub - shell has 1 electron.

Step3: Calculate total number of electrons in the ion

The total number of electrons in the ion is \(10 + 2+1=13\).

Step4: Find the neutral atom's electron number

Since the ion has a charge of + 1, the neutral atom has \(13 + 1=14\) electrons. The element with 14 electrons is silicon (Si), but the ion is \(Al^{+}\) because when aluminum (Al, atomic number 13) loses one electron, it forms a + 1 cation with the given electron - configuration.

Answer:

  1. \(Al^{+}\)
  2. 13
  3. 1