Question

balancing chemical reactions
date__//__
provide the coefficients to balance the chemical equations shown below.

1. h₂o + k₂o → koh
2. h₂o → h₂ + o₂
3. o₂ + n₂ → n₂o
4. h₂o + na → h₂ + naoh
5. na + i₂ → nai
6. cl₂ + ki → kcl + i₂
7. o₂ + ch₄ → h₂o + co₂
8. hcl + k₃po₄ → h₃po₄ + kcl
9. h₂o + co₂ → h₂co₃
10. h₂ + n₂ → nh₃
11. hcl + mg → h₂ + mgcl₂
12. h₂o₂ → h₂o + o₂
13. h₂so₄ + koh → h₂o + k₂so₄
14. kclo₃ → kcl + o₂
15. o₂ + s → so₃

Explanation:

Step1: Balance equation 1

$H_2O + K_2O
ightarrow 2KOH$

Step2: Balance equation 2

$2H_2O
ightarrow 2H_2+O_2$

Step3: Balance equation 3

$O_2 + 2N_2
ightarrow 2N_2O$

Step4: Balance equation 4

$2H_2O + 2Na
ightarrow H_2 + 2NaOH$

Step5: Balance equation 5

$2Na + I_2
ightarrow 2NaI$

Step6: Balance equation 6

$Cl_2 + 2KI
ightarrow 2KCl+I_2$

Step7: Balance equation 7

$2O_2 + CH_4
ightarrow 2H_2O + CO_2$

Step8: Balance equation 8

$3HCl + K_3PO_4
ightarrow H_3PO_4 + 3KCl$

Step9: Balance equation 9

$H_2O + CO_2
ightarrow H_2CO_3$ (already balanced)

Step10: Balance equation 10

$3H_2 + N_2
ightarrow 2NH_3$

Step11: Balance equation 11

$2HCl + Mg
ightarrow H_2 + MgCl_2$

Step12: Balance equation 12

$2H_2O_2
ightarrow 2H_2O + O_2$

Step13: Balance equation 13

$H_2SO_4 + 2KOH
ightarrow 2H_2O + K_2SO_4$

Step14: Balance equation 14

$2KClO_3
ightarrow 2KCl + 3O_2$

Step15: Balance equation 15

$3O_2 + 2S
ightarrow 2SO_3$

Answer:

1. $1H_2O + 1K_2O

ightarrow 2KOH$

1. $2H_2O

ightarrow 2H_2+1O_2$

1. $1O_2 + 2N_2

ightarrow 2N_2O$

1. $2H_2O + 2Na

ightarrow 1H_2 + 2NaOH$

1. $2Na + 1I_2

ightarrow 2NaI$

1. $1Cl_2 + 2KI

ightarrow 2KCl+1I_2$

1. $2O_2 + 1CH_4

ightarrow 2H_2O + 1CO_2$

1. $3HCl + 1K_3PO_4

ightarrow 1H_3PO_4 + 3KCl$

1. $1H_2O + 1CO_2

ightarrow 1H_2CO_3$

1. $3H_2 + 1N_2

ightarrow 2NH_3$

1. $2HCl + 1Mg

ightarrow 1H_2 + 1MgCl_2$

1. $2H_2O_2

ightarrow 2H_2O + 1O_2$

1. $1H_2SO_4 + 2KOH

ightarrow 2H_2O + 1K_2SO_4$

1. $2KClO_3

ightarrow 2KCl + 3O_2$

1. $3O_2 + 2S

ightarrow 2SO_3$