Question

6.bsu mathematical computation 6 pts use the table below to answer questions 28 - 30. a student used a balance and a graduated cylinder to collect the following data: sample mass 10.23 g volume of water 20.0 ml volume of water and sample 21.5 ml volume of sample 28) calculate the volume of the sample. show your work in the space below; put your final answers in the table above.(2pts) 29) calculate the density of the sample. show your work. include the appropriate number of significant figures and proper units.(2pts) 30) if the accepted value is 6.93 grams per milliliter, calculate the percent error. (2pts)

Explanation:

Step1: Calculate sample volume

The volume of the sample is the difference between the volume of water - and - sample and the volume of water. So, $V = 21.5\ ml-20.0\ ml = 1.5\ ml$.

Step2: Calculate sample density

Density $
ho=\frac{m}{V}$, where $m = 10.23\ g$ and $V = 1.5\ ml$. So, $
ho=\frac{10.23\ g}{1.5\ ml}=6.82\ g/ml$.

Step3: Calculate percent error

Percent error formula is $\text{Percent Error}=\frac{\vert\text{Experimental Value}-\text{Accepted Value}\vert}{\text{Accepted Value}}\times100\%$. Experimental value is $6.82\ g/ml$ and accepted value is $6.93\ g/ml$. So, $\text{Percent Error}=\frac{\vert6.82 - 6.93\vert}{6.93}\times100\%=\frac{0.11}{6.93}\times100\%\approx1.6\%$.

Answer:

1. $1.5\ ml$
2. $6.82\ g/ml$
3. $1.6\%$