Question

calculate the amount (mol) of solute, k₂cro₄, added to the solution. the molar mass of the solute is 194.19 g/mol. use this to convert from mass to moles. 2nd attempt recheck next (2 of 6) incorrect

Explanation:

Step1: Recall mole - mass formula

The formula to convert mass ($m$) to moles ($n$) is $n=\frac{m}{M}$, where $M$ is the molar mass. But we are not given the mass here. Assuming we have a mass value of $m$ grams of $K_2CrO_4$.

Step2: Let's assume a mass value for demonstration

Let's say we have $m = 194.19$ g of $K_2CrO_4$. Then $n=\frac{m}{M}$. Substituting $m = 194.19$ g and $M=194.19$ g/mol into the formula, we get $n=\frac{194.19\ g}{194.19\ g/mol}$.

Step3: Calculate the number of moles

$n = 1$ mol.

Answer:

If the mass of $K_2CrO_4$ is 194.19 g, the amount of solute is 1 mol. (Note: In a real - world problem, you need to be given the actual mass of $K_2CrO_4$ added to the solution to get a definite answer. Here we just demonstrated the process with an assumed mass equal to the molar mass for simplicity).